x^2-1002x+2000=0

Solution for x^2-1002x+2000=0 equation:

x^2-1002x+2000=0

a = 1; b = -1002; c = +2000;
Δ = b2-4ac
Δ = -10022-4·1·2000
Δ = 996004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{996004}=998$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1002)-998}{2*1}=\frac{4}{2}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1002)+998}{2*1}=\frac{2000}{2}
=1000
$